1:
a: 2x-3=5
=>2x=8
=>x=4
b: (x+2)(3x-15)=0
=>x+2=0 hoặc 3x-15=0
=>x=5 hoặc x=-2
c: \(\dfrac{3}{x+1}-\dfrac{2}{x-2}=\dfrac{4x-2}{\left(x+1\right)\left(x-2\right)}\)
=>\(\dfrac{3x-6-2x-2}{\left(x+1\right)\left(x-2\right)}=\dfrac{4x-2}{\left(x+1\right)\left(x-2\right)}\)
=>4x-2=x-8
=>3x=-6
=>x=-2(nhận)
a: =>2/3x+2/3<2+1/2x-1
=>2/3x+2/3<1/2x+1
=>2/3x-1/2x<1/3
=>1/6x<1/3
=>x<1/3:1/6=2
b: 3x-4<5x-6
=>-2x<-2
=>x>1
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