Question

Answer 1

\(\left(-\dfrac{1}{4}\right)^2\left(\dfrac{4}{11}+\dfrac{7}{11}\right)=\left(-\dfrac{1}{4}\right)^2\cdot1=\dfrac{1}{16}\)

Answer 2

giúp tớ vs

Answer 3

1 / 4

Answer 4

1/4

Answer 5

29/44

Answer 6

= (-1/4)². ( 4/11 + 7/11)

= (-1/4)². 1

= 1/16 . 1 

= 1/16

Answer 7

\(\dfrac{1}{16}\)

Answer 8

1/4

Answer 9

d, =\(\left(\dfrac{-1}{4}\right)^2.\left(\dfrac{4}{11}+\dfrac{7}{11}\right)\)
    =\(\dfrac{1}{16}\).1
    =\(\dfrac{1}{16}\)

Answer 10

d) \(\left(-\dfrac{1}{4}\right)^2\cdot\dfrac{4}{11}+\dfrac{7}{11}\cdot\left(-\dfrac{1}{4}\right)^2=\dfrac{1}{16}\cdot\dfrac{4}{11}+\dfrac{7}{11}\cdot\dfrac{1}{16}=\dfrac{1}{16}\cdot\left(\dfrac{4}{11}+\dfrac{7}{11}\right)=\dfrac{1}{16}\cdot1=\dfrac{1}{16}\)

Answer 11

\(( -1/2)^2 . 4 /11 + 7 /11 . (-1/2)^2 . (4/11 + 7/11)=(-1/2)^2 . 11/11 = 1/4\)

Answer 12

1/16