a: 2x+7=32-3x
=>5x=25
hay x=5
b: \(\Leftrightarrow6\left(x+4\right)+30\left(-x+4\right)=10x-15\left(x-2\right)\)
\(\Leftrightarrow6x+24-30x+120=10x-15x+30\)
=>-24x+144=-5x+30
=>x=6
c: \(\Leftrightarrow\left(x+3\right)\left(x-5\right)+\left(x-3\right)\left(x+3\right)=0\)
=>(x+3)(x-5+x-3)=0
=>(x+3)(2x-8)=0
=>x=-3 hoặc x=4
a. 7 + 2x = 32 - 3x
<=> 2x + 3x = 32 - 7
<=> 5x = 25
<=> x = 5
b. \(\dfrac{x+4}{5}-x+4=\dfrac{x}{3}-\dfrac{x-2}{2}\)
⇔ \(\dfrac{x+4}{5}-x+\dfrac{4}{1}=\dfrac{x}{3}-\dfrac{x-2}{2}\)
⇔ \(\dfrac{x+24}{5}-x=\dfrac{x}{3}-\dfrac{x-2}{2}\)
⇔ \(6\left(x+24\right)-30x=-5x+30\)
⇔ \(-24x+5x=30-144\)
⇔ \(19x=114\)
⇔ \(x=114:9\)
⇔ \(x=6\)
