Question

Answer 1

a: Khi x=4 thì \(B=\dfrac{4-3}{2\cdot4-4^2}=\dfrac{1}{-8}\)

b: \(A=\dfrac{-4x^2-x^2-4x-4+x^2-4x+4}{\left(x-2\right)\left(x+2\right)}=\dfrac{-4x^2-8x}{\left(x-2\right)\left(x+2\right)}=\dfrac{-4x}{x-2}\)

c: P=A:B

=-4x/(x-2):(x-3)/2x-x^2

\(=\dfrac{4x}{x-2}\cdot\dfrac{x\left(x-2\right)}{x-3}=\dfrac{4x^2}{x-3}\)

P<0

=>x-3<0

=>x<3

d: P=-1

=>4x^2=-x+3

=>4x^2+x-3=0

=>(x+1)(4x-3)=0

=>x=3/4 hoặc x=-1

e: A nguyên

=>-4x chia hết cho x-2

=>4x-8+8 chia hết cho x-2

=>x-2 thuộc {1;-1;2;-2;4;-4;8;-8}

=>x thuộc {3;1;4;6;0;10;-6}