a: \(1\dfrac{2}{3}+x=-\dfrac{11}{3}\)
=>\(x+\dfrac{5}{3}=-\dfrac{11}{3}\)
=>\(x=-\dfrac{11}{3}-\dfrac{5}{3}=-\dfrac{16}{3}\)
b: \(\dfrac{2}{3}+\dfrac{1}{3}:x=\dfrac{3}{4}\)
=>\(\dfrac{1}{3}:x=\dfrac{3}{4}-\dfrac{2}{3}=\dfrac{9-8}{12}=\dfrac{1}{12}\)
=>\(x=\dfrac{1}{3}:\dfrac{1}{12}=\dfrac{1}{3}\cdot12=4\)