Question

Answer 1

Câu 13: A

Câu 14: C

Câu 15: B

Câu 16: \(\dfrac{x+1}{2}+\dfrac{x+3}{4}=3-\dfrac{x+2}{3}\)

=>\(\dfrac{6\left(x+1\right)}{12}+\dfrac{3\left(x+3\right)}{12}=\dfrac{36-4\left(x+2\right)}{12}\)

=>6(x+1)+3(x+3)=36-4(x+2)

=>6x+6+3x+9+4x+8=36

=>13x+23=36

=>13x=13

=>x=1

=>S={1}

Câu 17:

Thay x=0 vào phương trình, ta được:

\(2\cdot0+m-3=0\)

=>m-3=0

=>m=3

=>Chọn A

Câu 18:

x(2x-7)=2(2x-7)

=>x(2x-7)-2(2x-7)=0

=>(2x-7)(x-2)=0

=>\(\left[{}\begin{matrix}2x-7=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=2\end{matrix}\right.\)

=>Chọn B