\(10A=\dfrac{10^{2021}+10}{10^{2021}+1}=1+\dfrac{9}{10^{2021}+1}\)
\(10B=\dfrac{10^{2022}+10}{10^{2022}+1}=1+\dfrac{9}{10^{2022}+1}\)
Ta có: \(10^{2021}+1< 10^{2022}+1\)
=>\(\dfrac{9}{10^{2021}+1}>\dfrac{9}{10^{2022}+1}\)
=>\(\dfrac{9}{10^{2021}+1}+1>\dfrac{9}{10^{2022}+1}+1\)
=>10A>10B
=>A>B