Question

Answer 1

\(\left[\left(\dfrac{2}{1006}-\dfrac{3}{2012}\right)\cdot\dfrac{1006}{99}+\dfrac{197}{198}\right]:\left[\left(\dfrac{1}{1007}+\dfrac{2}{2014}\right)\cdot\dfrac{1007}{99}-\dfrac{1}{99}\right]+1923\)

\(=\left[\dfrac{4-3}{2012}\cdot\dfrac{1006}{99}+\dfrac{197}{198}\right]:\left[\dfrac{2}{1007}\cdot\dfrac{1007}{99}-\dfrac{1}{99}\right]+1923\)

\(=\left(\dfrac{1}{198}+\dfrac{197}{198}\right):\left(\dfrac{2}{99}-\dfrac{1}{99}\right)+1923\)

\(=1:\dfrac{1}{99}+1923=1923+99=2022\)

=>Chọn C