Câu 10: B
Câu 11: \(\left(3x-5\right)^2-\left(x-2\right)^2=0\)
=>(3x-5-x+2)(3x-5+x-2)=0
=>(2x-3)(4x-7)=0
=>\(\left[\begin{array}{l}2x-3=0\\ 4x-7=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac32\\ x=\frac74\end{array}\right.\)
=>Chọn A
Câu 12: C
Câu 13: C


