a, đk : x khác 0 ; -5 ; 5
\(\dfrac{x+25}{2\left(x^2-25\right)}-\dfrac{x+5}{x\left(x-5\right)}=\dfrac{5-x}{2x\left(x+5\right)}\)
\(\Rightarrow x^2+25x-2\left(x+5\right)=\left(5-x\right)\left(x-5\right)\)
\(\Leftrightarrow x^2+23x-10=-x^2+10x-25\Leftrightarrow2x^2+13x+15=0\Leftrightarrow x=-\dfrac{3}{2}\left(tm\right);x=-5\left(ktm\right)\)
b, đk x khác -3 ; 1
\(4=\left(2x-5\right)\left(x-1\right)-2x\left(x+3\right)\)
\(\Leftrightarrow-7x+5-6x=4\Leftrightarrow-13x=-1\Leftrightarrow x=\dfrac{1}{13}\left(tm\right)\)
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