Question

Answer 1

a: \(A=2\cdot2^2-\dfrac{1}{3}\cdot9=8-3=5\)

b: \(B=\dfrac{1}{2}\cdot\left(-2\right)^2-3\cdot\left(-\dfrac{1}{3}\right)^2=\dfrac{1}{2}\cdot4-3\cdot\dfrac{1}{9}=2-\dfrac{1}{3}=\dfrac{5}{3}\)

c: \(C=\left(2x+y\right)\left(x+y\right)=\left(2\cdot\dfrac{-1}{2}+\dfrac{2}{3}\right)\left(-\dfrac{1}{2}+\dfrac{2}{3}\right)\)

\(=\left(\dfrac{2}{3}-1\right)\left(\dfrac{-3+4}{6}\right)=\dfrac{-1}{3}\cdot\dfrac{1}{6}=\dfrac{-1}{18}\)