Bài 2:
a: \(=\dfrac{9}{4}+\left(-\dfrac{5}{11}-\dfrac{6}{11}\right)=\dfrac{9}{4}-1=\dfrac{5}{4}\)
b: \(=\left(-\dfrac{8}{7}-\dfrac{6}{7}\right)+\dfrac{4}{5}=-2+\dfrac{4}{5}=-\dfrac{6}{5}\)
c: \(=\left(-\dfrac{15}{9}-\dfrac{12}{9}\right)+\left(\dfrac{23}{7}+\dfrac{5}{7}\right)=4-3=1\)
