Question

Answer 1

Bài 2: 

a: 2(x-1)-31=9

=>2(x-1)=40

=>x-1=20

hay x=21

b: \(\left(x^2+4\right)\left(3-x\right)=0\)

=>3-x=0

hay x=3

c: \(\dfrac{x}{-48}=\dfrac{2}{-3}\)

=>x/48=2/3

hay x=32

d: \(4\left(2-x\right)-3\left(2x-1\right)=-6\)

=>8-4x-6x+3=-6

=>-10x+11=-6

=>-10x=-17

hay x=17/10

e: \(\left(2x-3\right)\left(6-2x\right)=0\)

=>2x-3=0 hoặc 6-2x=0

=>x=3/2 hoặc x=3