Question

Answer 1

\(a,2x+36:12=53\\ \Rightarrow2x+3=53\\ \Rightarrow2x=50\\ \Rightarrow x=25\\ b,\left|x+7\right|=\left|-15\right|\\ \Rightarrow\left[{}\begin{matrix}x+7=-15\\x+7=15\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-22\\x=8\end{matrix}\right.\\ c,\left(3x-1\right)^3=125\\ \Rightarrow\left(3x-1\right)^3=5^3\\ \Rightarrow3x-1=5\\ \Rightarrow3x=6\\ \Rightarrow x=2\\ d,x^{2021}=x\\ \Rightarrow x\left(x^{2020}-1\right)=0\)

\(\Rightarrow x=0\) hoặc x²⁰²⁰=1

\(\Rightarrow x=0\) hoặc x=\(\pm\)1

Answer 2

a, \(2x+3=53\Leftrightarrow2x=50\Leftrightarrow x=25\)

b, \(\left|x+7\right|=15\Leftrightarrow\left[{}\begin{matrix}x+7=15\\x+7=-15\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-22\end{matrix}\right.\)

c, \(3x-1=5\Leftrightarrow3x=6\Leftrightarrow x=2\)

d, \(x^{2021}-x=0\Leftrightarrow x\left(x^{2020}-1\right)=0\Leftrightarrow x=0;x=-1;x=1\)