Bài 4:
\(=\left(\dfrac{13}{8}+\dfrac{11}{8}\right)+\left(\dfrac{7}{6}+\dfrac{5}{6}\right)=\dfrac{24}{8}+\dfrac{12}{6}=3+2=5\)
Bài 2:
a: \(x+\dfrac{1}{6}=\dfrac{5}{2}-\dfrac{1}{4}=\dfrac{10}{4}-\dfrac{1}{4}=\dfrac{9}{4}\)
=>x=9/4-1/6=27/12-2/12=25/12
b: \(\dfrac{x}{24}-\dfrac{3}{8}=\dfrac{5}{6}\)
\(\Leftrightarrow x\cdot\dfrac{1}{24}=\dfrac{5}{6}+\dfrac{3}{8}=\dfrac{20}{24}+\dfrac{9}{24}=\dfrac{29}{24}\)
hay x=29
