\(a,\dfrac{11\times3}{10\times3}-\dfrac{2\times10}{3\times10}+\dfrac{4\times6}{5\times6}=\dfrac{33}{30}-\dfrac{20}{30}+\dfrac{24}{30}\\ =\dfrac{37}{30}\\ b,\dfrac{18\times3}{15\times3}+\dfrac{3\times9}{5\times9}-\dfrac{7}{45}=\dfrac{54+27-7}{45}=\dfrac{74}{45}\)
\(\dfrac{11}{10}-\dfrac{2}{3}+\dfrac{4}{5}=\dfrac{33}{30}-\dfrac{20}{30}+\dfrac{24}{30}=\dfrac{37}{30}\\ \dfrac{18}{15}+\dfrac{3}{5}-\dfrac{7}{45}=\dfrac{6}{5}+\dfrac{3}{5}-\dfrac{7}{45}=\dfrac{9}{5}-\dfrac{7}{45}=\dfrac{81}{45}-\dfrac{7}{45}=\dfrac{74}{45}\)
\(33/30-20/30+24/30=37/30\)
\(54/45+27/45-7/45=74/45\)
\(a,\dfrac{11}{10}-\dfrac{2}{3}+\dfrac{4}{5}=\dfrac{33-20+24}{30}=\dfrac{37}{30}\\ b,\dfrac{18}{15}+\dfrac{3}{5}-\dfrac{7}{45}=\dfrac{54+27-7}{45}=\dfrac{74}{45}\)
