\(=\dfrac{6}{7}\left(\dfrac{8}{13}+\dfrac{9}{13}-\dfrac{3}{13}\right)=\dfrac{6}{7}\cdot\dfrac{14}{13}=\dfrac{84}{91}=\dfrac{12}{13}\)
Đúng 2
Bình luận (0)
\(=\dfrac{6}{7}\left(\dfrac{8}{13}+\dfrac{9}{13}-\dfrac{3}{13}\right)=\dfrac{6}{7}\cdot\dfrac{14}{13}=\dfrac{84}{91}=\dfrac{12}{13}\)