a: \(\Leftrightarrow\dfrac{x-3}{2019}-1+\dfrac{x-2}{2020}-1=\dfrac{x-2020}{2}-1+\dfrac{x-2019}{3}-1\)
=>x-2022=0
hay x=2022
b: \(\Leftrightarrow x^4-x^3-4x^2+6x^3-6x^2-24x-4x^2+4x-16=0\)
\(\Leftrightarrow\left(x^2-x-4\right)\left(x^2+6x-4\right)=0\)
\(\Leftrightarrow x\in\left\{\dfrac{1+\sqrt{17}}{2};\dfrac{1-\sqrt{17}}{2};-3+\sqrt{13};-3-\sqrt{13}\right\}\)
a,
\(\Leftrightarrow\left(\dfrac{x-3}{2019}+1\right)+\left(\dfrac{x-2}{2020}+1\right)-\left(\dfrac{x-2020}{2}+1\right)-\left(\dfrac{x-2019}{3}+1\right)=0\)
\(\Leftrightarrow\dfrac{x-2016}{2019}+\dfrac{x-2018}{2020}-\dfrac{x-2018}{2}-\dfrac{x-2016}{3}=0\)
\(\Leftrightarrow x-2016+x-2018-x+2018+x+2016=0\)
\(\Leftrightarrow2x=0\Rightarrow x=0\)
