Question

Answer 1

a: \(=\dfrac{1}{5}\left(\dfrac{11}{16}+\dfrac{5}{16}\right)+\dfrac{4}{5}=\dfrac{1}{5}+\dfrac{4}{5}=1\)

b: \(=\dfrac{5}{9}\left(\dfrac{10}{11}+\dfrac{14}{11}-\dfrac{15}{11}\right)=\dfrac{5}{9}\cdot\dfrac{9}{11}=\dfrac{5}{11}\)

a: \(=\dfrac{-3}{5}\left(\dfrac{5}{7}+\dfrac{4}{7}-1\right)=\dfrac{-3}{5}\cdot\dfrac{2}{7}=\dfrac{-6}{35}\)

b: \(=\dfrac{-4}{9}\left(\dfrac{3}{11}+\dfrac{8}{11}\right)-\dfrac{5}{9}=\dfrac{-4}{9}-\dfrac{5}{9}=-1\)

a: \(=\dfrac{-5}{9}\left(\dfrac{2}{13}+\dfrac{11}{13}\right)-\dfrac{4}{9}=\dfrac{-5}{9}-\dfrac{4}{9}=-1\)