a: \(=\dfrac{3}{4}+\dfrac{27}{10}-1=\dfrac{49}{20}\)
b: \(=\dfrac{9}{17}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)=\dfrac{9}{17}\)
c: \(=\dfrac{6}{7}\left(\dfrac{8}{13}+\dfrac{9}{13}-\dfrac{3}{13}\right)=\dfrac{6}{7}\cdot\dfrac{14}{13}=\dfrac{12}{13}\)
a: \(=\dfrac{8}{5}-\dfrac{21}{5}\cdot\dfrac{3}{2}=\dfrac{8}{5}-\dfrac{63}{10}=\dfrac{-47}{10}\)
