c: \(=\dfrac{4\cdot2+5}{10}\cdot\dfrac{39-120}{195}=\dfrac{13}{10}\cdot\dfrac{-81}{195}=\dfrac{-81}{10\cdot15}=\dfrac{-81}{150}=\dfrac{-27}{50}\)
d: \(=\dfrac{1}{9}\cdot\dfrac{9}{25}\cdot\dfrac{15}{22}=\dfrac{15}{25}\cdot\dfrac{1}{22}=\dfrac{3}{5\cdot22}=\dfrac{3}{110}\)
