g: =>2x-3<=0
=>x<=3/2
h: =>3-x>=0
hay x<=3
g,\(\Leftrightarrow2x-3-3+2x=0\)
\(\Leftrightarrow4x-6=0\)
\(x=\dfrac{6}{4}=\dfrac{3}{2}\)
g, Với x =< 3/2
TH1 : \(2x-3=3-2x\Leftrightarrow4x=6\Leftrightarrow x=\dfrac{3}{2}\left(tm\right)\)
TH2 : \(3-2x=3-2x\)* vô lí *
h, Với x =< 3
TH1 : \(3-x=3-x\)* vô lí *
TH2 : \(x-3=3-x\Leftrightarrow2x=6\Leftrightarrow x=3\)(tm)