Question

Answer 1

a: \(=\dfrac{7}{13}\cdot\dfrac{7}{15}-\dfrac{5}{12}\cdot\dfrac{7}{13}+\dfrac{7}{13}\cdot\dfrac{8}{15}\)

\(=\dfrac{7}{13}\left(\dfrac{7}{15}-\dfrac{5}{12}+\dfrac{8}{15}\right)=\dfrac{7}{13}\cdot\dfrac{7}{12}=\dfrac{49}{156}\)

b: \(=\left(\dfrac{12}{199}+\dfrac{23}{200}-\dfrac{34}{201}\right)\cdot\dfrac{3-2-1}{6}=0\)