Bài 10:
\(10A=\dfrac{10^{2003}+1+9}{10^{2003}+1}=1+\dfrac{9}{10^{2003}+1}\)
\(10B=\dfrac{10^{2004}+1+9}{10^{2004}+1}=1+\dfrac{9}{10^{2004}+1}\)
mà \(10^{2003}+1< 10^{2004}+1\)
nên 10A>10B
hay A>B
Bài 3:
\(2003A=\dfrac{2003^{2004}+1+2002}{2003^{2004}+1}=1+\dfrac{2002}{2003^{2004}+1}\)
\(2003B=\dfrac{2003^{2003}+1+2002}{2003^{2003}+1}=1+\dfrac{2002}{2003^{2003}+1}\)
mà \(2003^{2004}+1>2003^{2003}+1\)
nên A<B
Đúng 4
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