1) ĐKXĐ: \(x\ne1\)
\(pt\Leftrightarrow\dfrac{2x-1+x-1-1}{x-1}=0\Leftrightarrow3x-3=0\Leftrightarrow3x=3\Leftrightarrow x=1\left(ktm\right)\)
Vậy \(S=\varnothing\)
2) ĐKXĐ: \(x\ne7\)
\(pt\Leftrightarrow\dfrac{x-8-8\left(x-7\right)+1}{x-7}=0\Leftrightarrow-7x+49=0\Leftrightarrow x=7\left(ktm\right)\)
Vậy \(S=\varnothing\)
3) ĐKXĐ: \(x\ne2\)
\(pt\Leftrightarrow\dfrac{1+3\left(x-2\right)-\left(3-x\right)}{x-2}=0\Leftrightarrow4x-8=0\Leftrightarrow x=2\left(ktm\right)\Rightarrow S=\varnothing\)
4) ĐKXĐ: \(x\ne2\)
\(pt\Leftrightarrow\dfrac{1+3\left(x-2\right)+x-3}{x-2}=0\Leftrightarrow4x-8=0\Leftrightarrow x=2\left(ktm\right)\Rightarrow S=\varnothing\)
5) ĐKXĐ: \(x\ne-1\)
\(pt\Leftrightarrow\dfrac{5x+2x+2+12}{2\left(x+1\right)}=0\Leftrightarrow7x+14=0\Leftrightarrow x=-2\left(tm\right)\)
6) ĐKXĐ: \(x\ne0,x\ne2\)
\(pt\Leftrightarrow\dfrac{x\left(x+2\right)-\left(x-2\right)-2}{x\left(x-2\right)}=0\Leftrightarrow x^2+x+2=0\Leftrightarrow\left(x+\dfrac{1}{2}\right)^2+\dfrac{3}{4}=0\left(VLý\right)\Rightarrow S=\varnothing\)
1: =>2x-1+x-1=1
=>3x-2=1
=>3x=3
hay x=1(loại)
2: \(\Leftrightarrow\dfrac{-1}{x-7}=\dfrac{x-8}{x-7}-\dfrac{8\left(x-7\right)}{x-7}\)
=>x-8-8x+56=-1
=>-7x+48=-1
=>-7x=-49
hay x=7(loại)
3: \(\Leftrightarrow1+3\left(x-2\right)=3-x\)
=>3x-6+1-3+x=0
=>4x-8=0
hay x=2(loại)
8: \(\Leftrightarrow3\left(x+1\right)=-3x-2-4\left(x-1\right)\)
=>3x+3=-3x-2-4x+4
=>3x+3=-7x+2
=>10x=-1
hay x=-1/10(nhận)
