Question

Answer 1

\(\dfrac{x+2}{6}+\dfrac{3-2x}{4}>\dfrac{x-1}{3}+\dfrac{1}{2}\)

\(\Leftrightarrow\dfrac{2\left(x+2\right)+3\left(3-2x\right)}{12}>\dfrac{4\left(x-1\right)+6}{12}\)

\(\Leftrightarrow-4x+13>4x+2\Leftrightarrow8x< 11\Leftrightarrow x< \dfrac{11}{8}\)

Em tự biểu diễn tập nghiệm nhé !

Answer 2

\(\Leftrightarrow2\left(x+2\right)+3\left(3-2x\right)>4\left(x-1\right)+6\)

\(\Leftrightarrow2x+4+9-6x>4x-4+6\)

\(\Leftrightarrow-4x+13-4x-2>0\)

\(\Leftrightarrow-8x+11>0\)

=>-8x>-11

hay x<11/8