Tam giác ABC, có DE//BC
Theo định lí ta-lét, ta có :
\(\Rightarrow\dfrac{AD}{DB}=\dfrac{AE}{EC}\)
hay \(\dfrac{12}{18}=\dfrac{AE}{30}\)
\(\Rightarrow AE=\dfrac{30.12}{18}=20\left(cm\right)\)
Vậy AE 20 cm
Xét tam giác ABC: DE // BC (gt).
\(\Rightarrow\dfrac{AD}{BD}=\dfrac{AE}{CE}\left(Talet\right).\)
\(Thay:\) \(\dfrac{12}{18}=\dfrac{AE}{30}.\Rightarrow AE=20\) (đvđd).