d: =>y=-67x5:67=-5
e: =>2x=-90/81=-10/9
hay x=-5/9
d, \(\dfrac{67}{5}\) = \(\dfrac{-67}{y}\)
\(\Leftrightarrow\) 67y = -67 . 5
\(\Leftrightarrow\) 67y = -335
\(\Leftrightarrow\) y = -335 : 67
\(\Leftrightarrow\) y = -5
Vậy y = -5
e, \(\dfrac{2x}{-9}\) = \(\dfrac{10}{81}\)
\(\Leftrightarrow\) 2x . 81 = 10. (-9)
\(\Leftrightarrow\) 162x = -90
\(\Leftrightarrow\) x = -90 : 162
\(\Leftrightarrow\) x = \(\dfrac{-5}{9}\)
Vậy x = \(\dfrac{-5}{9}\)
