Ta có: \(n_{O_2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\)
a, PT: \(C+O_2\underrightarrow{t^o}CO_2\)
____0,1__0,1___0,1 (mol)
\(\Rightarrow m_C=0,1.12=1,2\left(g\right)\)
\(V_{CO_2}=0,1.22,4=2,24\left(l\right)\)
b, PT: \(S+O_2\underrightarrow{t^o}SO_2\)
_____0,1__0,1__0,1 (mol)
\(\Rightarrow m_S=0,1.32=3,2\left(g\right)\)
\(V_{SO_2}=0,1.22,4=2,24\left(l\right)\)
c, PT: \(4P+5O_2\underrightarrow{t^o}2P_2O_5\)
____0,08__0,1____0,04 (mol)
\(\Rightarrow m_P=0,08.31=2,48\left(g\right)\)
\(m_{P_2O_5}=0,04.142=5,68\left(g\right)\)
Bạn tham khảo nhé!
\(n_{O_2}=\dfrac{V}{22,4}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\\ a,PTHH:C+O_2\underrightarrow{t^o}CO_2\\ Theo.PTHH:n_{CO_2}=n_{O_2}\\ \Rightarrow V_{CO_2}=V_{O_2}=2,24\left(l\right)\)
\(b,PTHH:S+O_2\underrightarrow{t^o}SO_2\\ Theo.PTHH:n_S=n_{SO_2}=n_{O_2}=0,1\left(mol\right)\\ \Rightarrow V_{SO_2}=V_{O_2}=2,24\left(l\right)\\ m_S=n.M=0,1.32=3,2\left(g\right)\)
\(c,PTHH:4P+5O_2\underrightarrow{t^o}2P_2O_5\\ Theo.PTHH:n_P=\dfrac{4}{5}.n_{O_2}=\dfrac{4}{5}.0,1=0,08\left(mol\right)\\ m_P=n.M=0,08.31=2,48\left(g\right)\\ Theo.PTHH:n_{P_2O_5}=\dfrac{2}{5}.n_{O_2}=\dfrac{2}{5}.0,1=0,04\left(mol\right)\\ m_{P_2O_5}=n.M=0,04.142=5,68\left(g\right)\)
