\(2x\left(x+1\right)-\left(2x+5\right)\left(x-3\right)=97\\ \Leftrightarrow\left(2x^2+2x\right)-\left(2x^2+5x-6x-15\right)=97\\ \Leftrightarrow2x^2+2x-\left(2x^2-x-15\right)=97\\ \Leftrightarrow2x^2+2x-2x^2+x+15-97=0\)
\(\Leftrightarrow3x-82=0\\ \Leftrightarrow3x=82\\ \Leftrightarrow x=\dfrac{82}{3}\)
Vậy pt có tập nghiệm \(S=\left\{\dfrac{82}{3}\right\}\)
\( \begin{array}{l} 2x( x+1) -( 2x+5)( x-3) =97\\ \Leftrightarrow \ 2x^{2} +2x-2x^{2} +x+15=97\\ \Leftrightarrow 3x=82\ \Leftrightarrow \ x=\frac{82}{3}\\ Vậy\ S=\left\{\frac{82}{3}\right\} \end{array}\)
