\(A=\dfrac{-4+3}{10}:\left(\dfrac{-2}{5}+\dfrac{10}{3}\right)=\dfrac{-1}{10}:\dfrac{44}{15}=\dfrac{-1}{10}\cdot\dfrac{15}{44}=\dfrac{-15}{440}=-\dfrac{3}{88}\)
\(B=\left|\dfrac{-4+3}{6}\right|\cdot\left(\dfrac{-4}{5}-\dfrac{1}{2}\right)=\dfrac{1}{6}\cdot\dfrac{-13}{10}=\dfrac{-13}{60}\)
