Question

Answer 1

1) ĐKXĐ: \(x\ne\pm\dfrac{3}{2}\)

\(A=\dfrac{\left(2x-3\right)^2}{\left(2x-3\right)\left(2x+3\right)}=\dfrac{2x-3}{2x+3}\)

2) Với \(x=-\dfrac{3}{4}\left(tm\right):\)

 \(A=\dfrac{2x-3}{2x+3}=\dfrac{2\left(-\dfrac{3}{4}\right)-3}{2\left(-\dfrac{3}{4}\right)+3}=-3\)

Answer 2

1: \(A=\dfrac{\left(2x-3\right)^2}{\left(2x+3\right)\left(2x-3\right)}=\dfrac{2x-3}{2x+3}\)

2: \(A=\dfrac{2\cdot\dfrac{-3}{4}-3}{2\cdot\dfrac{-3}{4}+3}=-3\)