Bài 3:
a: \(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}=\dfrac{99}{100}\)
b: \(=\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot\dfrac{3}{4}\cdot...\cdot\dfrac{a}{a+1}=\dfrac{1}{a+1}\)
c: \(=-66\cdot\dfrac{17}{66}+124\cdot\left(-37+63\right)\)
=-17+124x26
=3207
d: \(=\dfrac{7}{4}\left(\dfrac{11}{4}+\dfrac{33}{20}+\dfrac{33}{30}+\dfrac{33}{42}\right)=11\)
