Question

Answer 1

\(\Leftrightarrow\left\{{}\begin{matrix}x-3,4=0\\2,6-x=0\end{matrix}\right.\Leftrightarrow x\in\varnothing\)

Answer 2

\(\left|x-3,4\right|+\left|2,6-x\right|=0\)

\(\Rightarrow x-3,4=0\Leftrightarrow x=3,4\)

\(\Rightarrow2,6-x=0\Leftrightarrow x=2,6\)

\(\text{Cả hai trường hợp đều vô lí}\)

\(\Rightarrow x\in\varnothing\)