Question

Answer 1

\(\left|x+\dfrac{3}{4}\right|-\dfrac{1}{2}=0\)

\(\left|x+\dfrac{3}{4}\right|\)         \(=0+\dfrac{1}{2}=\dfrac{1}{2}\)

\(\text{Vậy }x+\dfrac{3}{4}=\dfrac{1}{2}\)

       \(x\)         \(=\dfrac{1}{2}-\dfrac{3}{4}=\dfrac{-1}{4}\)

\(\text{hoặc }x+\dfrac{3}{4}=\dfrac{-1}{2}\)

        \(x\)         \(=\left(\dfrac{-1}{2}\right)-\dfrac{3}{4}=\dfrac{-5}{4}\)

\(\Rightarrow x\in\left\{\left(\dfrac{-1}{4}\right);\left(\dfrac{-5}{4}\right)\right\}\)

Answer 2

-0.25

Answer 3

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{3}{4}=\dfrac{1}{2}\\x+\dfrac{3}{4}=-\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{4}\\x=-\dfrac{5}{4}\end{matrix}\right.\)