Question

Answer 1

\(=\dfrac{3\left(x+1\right)}{x\left(x+2\right)}+\dfrac{-3x}{\left(x+2\right)\left(x-2\right)}\)

\(=\dfrac{3\left(x^2-x-2\right)-3x^2}{x\left(x+2\right)\left(x-2\right)}\)

\(=\dfrac{-3\left(x+2\right)}{x\left(x+2\right)\left(x-2\right)}=\dfrac{-3}{x\left(x-2\right)}\)

Answer 2

= 3 ( x + 1 ) x ( x + 2 ) + − 3 x ( x + 2 ) ( x − 2 ) = 3 ( x 2 − x − 2 ) − 3 x 2 x ( x + 2 ) ( x − 2 ) = − 3 ( x + 2 ) x ( x + 2 ) ( x − 2 ) = − 3 x ( x − 2 )