Question

Answer 1

a) \(4x^2-4y^2=4\left(x^2-y^2\right)=4\left(x+y\right)\left(x-y\right)\)

b) \(=x\left(x+y\right)-2\left(x+y\right)=\left(x+y\right)\left(x-2\right)\)

c) \(6x^2-7x+2=6x^2-4x-3x+2=\left(2x-1\right)\left(3x-2\right)\)

Bài 2  : Bị mờ

Bài 3 : Mờ

 

 

Answer 2

Bài 3: 

a: Thay x=5 vào B, ta được:

B=(5-1)/(5+3)=2/8=1/4

b: \(A=\dfrac{2x^2+6x+x^2-3x-2x^2-3x-1}{\left(x-3\right)\left(x+3\right)}=\dfrac{-1}{\left(x-3\right)\left(x+3\right)}\)