Bài 1:
2: \(\left(-3\right)^{20}\cdot5^{40}=3^{20}\cdot\left(5^2\right)^{20}=3^{20}\cdot25^{20}=75^{20}\)
3: \(\frac{8^{20}+4^{20}}{4^{25}+64^5}\)
\(=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}=1024\)
Bài 2:
a: \(\sqrt{40+2}<\sqrt{40}+\sqrt2\)
b: \(\sqrt{625}-\frac{1}{\sqrt5}>\sqrt{576}-\frac{1}{\sqrt6}+1\)