a: \(M=\dfrac{x^2-x+x+1+2x}{\left(x-1\right)\left(x+1\right)}\cdot\dfrac{2x}{x+1}\)
\(=\dfrac{\left(x+1\right)^2}{\left(x+1\right)^2}\cdot\dfrac{2x}{x-1}=\dfrac{2x}{x-1}\)
b: Thay x=1/2 vào M, ta được:
\(M=\dfrac{2\cdot\dfrac{1}{2}}{\dfrac{1}{2}-1}=\dfrac{1}{-\dfrac{1}{2}}=-2\)
c: Để M nguyên thì \(x-1\in\left\{1;-1;2;-2\right\}\)
hay \(x\in\left\{2;0;3\right\}\)