Question

Answer 1

a) \(n_{Zn}=\dfrac{13}{65}=0,2\left(mol\right)\)

PTHH: Zn + H₂SO₄ --> ZnSO₄ + H₂

_____0,2--->0,2------->0,2---->0,2

=> m_H2SO4 = 0,2.98 = 19,6 (g)

b) m_ZnSO4 = 0,2.161 = 32,2 (g)

c) V_H2 = 0,2.22,4 = 4,48(l)

Answer 2

a: \(n_{Zn}=\dfrac{m}{M}=\dfrac{13}{65}=0.2\left(mol\right)\)

\(\Leftrightarrow n_{H_2SO_4}=0.2\left(mol\right)\)

\(\Leftrightarrow m_{H_2SO_4}=n_{H_2SO_4}\cdot M_{H_2SO_4}=0.2\cdot97=19.4\left(g\right)\)

b: \(m_{ZnSO_4}=0.2\cdot161=32.2\left(g\right)\)