\(a,P=\dfrac{x^2-2x+2x+4-2x-4}{\left(x-2\right)\left(x+2\right)}=\dfrac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{x}{x+2}\\ b,\left|x+1\right|=3\Leftrightarrow\left[{}\begin{matrix}x+1=3\\x+1=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\left(ktm\right)\\x=-4\left(tm\right)\end{matrix}\right.\\ \Leftrightarrow P=\dfrac{-4}{-4+2}=2\\ c,P=\dfrac{x+2-2}{x+2}=1-\dfrac{2}{x+2}\in Z\\ \Leftrightarrow x+2\inƯ\left(2\right)=\left\{-2;-1;1;2\right\}\\ \Leftrightarrow n\in\left\{-4;-3;-1;0\right\}\left(tm\right)\)
a: \(P=\dfrac{x^2-2x+2x+4-2x-4}{\left(x+2\right)\left(x-2\right)}=\dfrac{x}{x-2}\)
