Question

Answer 1

b: =>x(3x-2)=0

=>x=0 hoặc x=2/3

Answer 2

\(a,\Leftrightarrow2x^2-x-2x^2-2=0\\ \Leftrightarrow-x-2=0\Leftrightarrow x=-2\\ b,\Leftrightarrow x\left(3x-2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{2}{3}\end{matrix}\right.\\ c,\Leftrightarrow x^2\left(x+1\right)-4\left(x+1\right)=0\\ \Leftrightarrow\left(x-2\right)\left(x+2\right)\left(x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=-2\\x=-1\end{matrix}\right.\)