Question

Answer 1

a: \(=3x^2-6x-3x^2+1=-6x+1\)

d: \(=\dfrac{x+3x}{x+1}=\dfrac{4x}{x+1}\)

Answer 2

\(a,=3x^2-6x-3x^2+1=1-6x\\ b,=4x^2-4xy+y^2-4x^2+4xy=y^2\\ c,=x^3+3x^2y+3xy^2-x^3-3x^2y-3xy^2-y^3=-y^3\\ d,=\dfrac{x^2-x+3x^2-3x}{\left(x-1\right)\left(x+1\right)}=\dfrac{4x\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}=\dfrac{4x}{x+1}\)