\(R_{12}=R_1+R_2=1+5=6\Omega\)
\(R_{tđ}=\dfrac{R_3\cdot R_{12}}{R_3+R_{12}}=\dfrac{12\cdot6}{12+6}=4\Omega\)
\(I=\dfrac{\xi}{r+R}=\dfrac{3}{4+1}=0,6A\)
\(U_{12}=U_3=U=I\cdot R=0,6\cdot4=2,4V\)
\(I_2=I_{12}=\dfrac{U_{12}}{R_{12}}=\dfrac{2,4}{6}=0,4A\)
\(U_2=I_2\cdot R_2=0,4\cdot5=2V\)
\(P=U\cdot I=2,4\cdot0,6=1,44W\)
\(H=\dfrac{R}{r+R}=\dfrac{4}{1+4}=80\%\)
Đáp án lần lượt là D-C-C