Question

Answer 1

Bài 2: 

a: Để A nguyên thì \(x+3\in\left\{1;-1;7;-7\right\}\)

hay \(x\in\left\{-2;-4;4;-10\right\}\)

Answer 2

Bài 1:

\(a,\Leftrightarrow\dfrac{2x-1}{x+3}-2>0\Leftrightarrow\dfrac{2x-1-2x-6}{x+3}>0\Leftrightarrow x+3< 0\left(-7< 0\right)\Leftrightarrow x< -3\\ b,\Leftrightarrow\dfrac{3-2x}{x+3}+2>0\Leftrightarrow\dfrac{3-2x+2x+6}{x+3}>0\Leftrightarrow x+3>0\left(9>0\right)\Leftrightarrow x>-3\)