\(P=\left(x^2-2xy+y^2\right)-2\left(x-y\right)+1+2\left(y^2-y+\dfrac{1}{4}\right)-\dfrac{1}{2}\\ P=\left(x-y-1\right)^2+2\left(y-\dfrac{1}{2}\right)^2-\dfrac{1}{2}\\ P_{min}=-\dfrac{1}{2}\Rightarrow\left\{{}\begin{matrix}x-y-1=0\\y-\dfrac{1}{2}=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\dfrac{3}{2}\\y=\dfrac{1}{2}\end{matrix}\right.\Rightarrow a^2-b^2=2\)

