4.2
\(a,\) x tln y nên \(\dfrac{y_1}{x_2}=\dfrac{y_2}{x_1}=\dfrac{y_1+y_2}{3+4}=\dfrac{14}{7}=2\Rightarrow\left\{{}\begin{matrix}y_1=2.3=6\\y_2=2.4=8\end{matrix}\right.\)
\(b,\) x tln y nên \(x_1y_1=x_2y_2\Rightarrow5x_1=2y_2\Rightarrow\dfrac{x_1}{2}=\dfrac{y_2}{5}=\dfrac{2x_1-3y_2}{4-15}=\dfrac{22}{-11}=-2\Rightarrow\left\{{}\begin{matrix}x_1=-2.2=-4\\y_2=-2.5=-10\end{matrix}\right.\)
