Question

Answer 1

\(\Leftrightarrow\left[{}\begin{matrix}3x-5=\dfrac{1}{2}x+3\\3x-5=-\dfrac{1}{2}x-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{5}{2}x=8\\\dfrac{7}{2}x=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8:\dfrac{5}{2}=\dfrac{16}{5}\\x=2:\dfrac{7}{2}=\dfrac{4}{7}\end{matrix}\right.\)