Question

Answer 1

a: ĐKXĐ: \(\begin{cases}2x-2<>0\\ 2-2x^2<>0\end{cases}\)

=>\(\begin{cases}2x<>2\\ 2x^2<>2\end{cases}\)

=>x∉{1;-1}

b: \(B=\frac{x}{2x-2}+\frac{x^2+1}{2-2x^2}\)

\(=\frac{x}{2\left(x-1\right)}-\frac{x^2+1}{2\left(x-1\right)\left(x+1\right)}\)

\(=\frac{x\left(x+1\right)-x^2-1}{2\left(x-1\right)\left(x+1\right)}=\frac{x-1}{2\left(x-1\right)\left(x+1\right)}=\frac{1}{2\left(x+1\right)}\)

c: \(B=-\frac12\)

=>\(\frac{1}{2\left(x+1\right)}=-\frac12\)

=>2(x+1)=-2

=>x+1=-1

=>x=-2(nhận)