Question

Answer 1

\(\Leftrightarrow x-3+x+3-x+2=0\)

hay x=-2

Answer 2

\(\Rightarrow x+x-\left(x+3\right)-\left(x+3\right)+\left(x-2\right)=0\\ \Rightarrow2x-2x-6+x-2=0\\ \Rightarrow x=8\)

Answer 3

f) x-[-x+(x+3)]-[(x+3)-(x-2)]=0
   x-(-x+x+3)-(x+3-x-2)=0
   x-3-1=0
   x-4=0
   x=0+4
   x=4